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📐 Mathematics  ·  Three Dimensional Geometry  ·  JEE

The equation of the plane containing line r = i + lambda*(2i+j-k) and parallel to i+j is:

Answer: x-y+z=1.

  • A 2x-y-z=2
  • B x-y+z=0
  • C x-y+z=1
  • D x+y+z=1

Correct answer: C. x-y+z=1

Explanation: The line passes through (1,0,0) with direction (2,1,-1). For the plane to also be parallel to i+j = (1,1,0), its normal must be perpendicular to both directions: normal = (2,1,-1) x (1,1,0) = (1*0-(-1)*1, (-1)*1-2*0, 2*1-1*1) = (1,-1,1). Plane through (1,0,0) with this normal: 1(x-1)-1(y-0)+1(z-0)=0, giving x-y+z=1.

zxyOP (x, y, z)

Three mutually perpendicular axes x, y, z meeting at the origin O, with a point P located by its (x, y, z) coordinates.

Concept context

Lines and planes in 3D space, direction cosines, distances, and angles

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