📐 Mathematics · Three Dimensional Geometry · JEE

The distance of the point (1, 2, 3) from the plane 2x − 3y + 6z − 11 = 0 is:

Answer: 3/7.

Correct answer: A. 3/7

Explanation: Distance = |2 − 6 + 18 − 11|/√(4 + 9 + 36) = 3/7.

Three mutually perpendicular axes x, y, z meeting at the origin O, with a point P located by its (x, y, z) coordinates.

Concept context

Lines and planes in 3D space, direction cosines, distances, and angles