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📐 Mathematics  ·  Three Dimensional Geometry  ·  JEE

The distance from origin to the plane ax + by + cz = d is:

Answer: |d| / sqrt(a 2 +b 2 +c 2 ).

  • A d
  • B d / (a+b+c)
  • C |d| / sqrt(a<sup>2</sup>+b<sup>2</sup>+c<sup>2</sup>)
  • D sqrt(a<sup>2</sup>+b<sup>2</sup>+c<sup>2</sup>)

Correct answer: C. |d| / sqrt(a<sup>2</sup>+b<sup>2</sup>+c<sup>2</sup>)

Explanation: Distance from origin to plane ax + by + cz = d is |d| / sqrt(a<sup>2</sup> + b<sup>2</sup> + c<sup>2</sup>).

zxyOP (x, y, z)

Three mutually perpendicular axes x, y, z meeting at the origin O, with a point P located by its (x, y, z) coordinates.

Concept context

Lines and planes in 3D space, direction cosines, distances, and angles

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