Zaymiey

📐 Mathematics  ·  Three Dimensional Geometry  ·  JEE

The distance between parallel planes 2x-2y+z+3=0 and 4x-4y+2z+5=0 is:

Answer: 1/6.

  • A 1/6
  • B 1/3
  • C 1/2
  • D 1

Correct answer: A. 1/6

Explanation: Rewrite second plane: divide by 2 → 2x−2y+z+5/2=0. Both planes have normal (2,−2,1). Distance = |d₁−d₂|/|n| = |3−5/2|/√(4+4+1) = (1/2)/3 = 1/6. Answer: 1/6.

zxyOP (x, y, z)

Three mutually perpendicular axes x, y, z meeting at the origin O, with a point P located by its (x, y, z) coordinates.

Concept context

Lines and planes in 3D space, direction cosines, distances, and angles

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