Zaymiey

📐 Mathematics  ·  Sequences and Series  ·  JEE

Sum of cubes: 1³ + 2³ + 3³ + ... + n³ =

Answer: n²(n+1)²/4.

  • A n(n+1)(2n+1)/6
  • B n²(n+1)²/4
  • C n(n+1)/2
  • D n(2n+1)/3

Correct answer: B. n²(n+1)²/4

Explanation: Sum of cubes = [n(n+1)/2]² = n²(n+1)²/4.

Each bar grows by the common difference d=3a1=2a2=5a3=8a4=11d=3

Bar heights for AP 2, 5, 8, 11 with the common difference d=3 marked between consecutive terms.

Concept context

Arithmetic progressions, geometric progressions, and sums

Read the full Sequences and Series notes →