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📐 Mathematics  ·  Sequences and Series  ·  JEE

Sum of first n terms of an AP with first term a and last term l:

Answer: n(a+l)/2.

  • A n(a+l)/2
  • B na + ld
  • C n(a-l)/2
  • D (a+l)/2

Correct answer: A. n(a+l)/2

Explanation: Sn = n(a+l)/2 = n/2 × (first term + last term).

Each bar grows by the common difference d=3a1=2a2=5a3=8a4=11d=3

Bar heights for AP 2, 5, 8, 11 with the common difference d=3 marked between consecutive terms.

Concept context

Arithmetic progressions, geometric progressions, and sums

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