📐 Mathematics · Sequences and Series · JEE

Sum of AP: a + (a+d) + (a+2d) + ... to n terms when a = 3, d = 2, n = 12:

Answer: 168.

Correct answer: B. 168

Explanation: S12 = 12/2 [6 + 11×2] = 6 × 28 = 168.

Bar heights for AP 2, 5, 8, 11 with the common difference d=3 marked between consecutive terms.

Concept context

Arithmetic progressions, geometric progressions, and sums