Answer: n(2n-1)(2n+1)/3.
- A n(2n-1)(2n+1)/3
- B n(n+1)(2n+1)/6
- C n²(n+1)
- D 2n(n+1)(2n+1)/3
Correct answer: A. n(2n-1)(2n+1)/3
Explanation: Sum of squares of first n odd numbers = n(2n-1)(2n+1)/3. Derived by subtracting sum of even squares from total sum of squares.
Bar heights for AP 2, 5, 8, 11 with the common difference d=3 marked between consecutive terms.
Concept context
Arithmetic progressions, geometric progressions, and sums