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📐 Mathematics  ·  Sequences and Series  ·  JEE

How many terms of AP: 18, 16, 14,... are needed for sum = 0?

Answer: 19.

  • A 17
  • B 18
  • C 19
  • D 20

Correct answer: C. 19

Explanation: Sn = 0. n/2 [2×18 + (n-1)(-2)] = 0. 36 - 2(n-1) = 0. n-1 = 18, n = 19.

Each bar grows by the common difference d=3a1=2a2=5a3=8a4=11d=3

Bar heights for AP 2, 5, 8, 11 with the common difference d=3 marked between consecutive terms.

Concept context

Arithmetic progressions, geometric progressions, and sums

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