Answer: (10, 10).
- A (0, 0)
- B (5, 0)
- C (10, 10)
- D (10/3, 10/3)
Correct answer: C. (10, 10)
Explanation: (10,10) violates x + 2y <= 10 since 10 + 20 = 30 is far greater than 10, so it lies well outside the feasible region. The true corners are (0,0), (5,0), (0,5), and the intersection (10/3, 10/3).
One-variable inequalities use open (excluded) or closed (included) circles on a number line; two-variable inequalities use a dashed (strict) or solid (non-strict) boundary line, with the solution being the entire shaded half-plane on one side of it.
Concept context
Solving linear inequalities in one and two variables algebraically and graphically, and representing solutions on a number line or as a region in a plane.