Zaymiey

📐 Mathematics  ·  Continuity and Differentiability  ·  JEE

The function f(x) = |x| is continuous everywhere but not differentiable at:

Answer: x = 0.

  • A x = 1
  • B x = 0
  • C x = −1
  • D nowhere

Correct answer: B. x = 0

Explanation: There is a corner at x = 0 where the left and right derivatives differ.

f(x) = |x|: Continuous but NOT Differentiable at 0x=0 (sharp "kink")LHD = -1RHD = +1LHD ≠ RHD at the kink → not differentiable, even though the curve has no gap (continuous)

f(x)=|x| is perfectly continuous at x=0 (no break, no jump), but the curve has a sharp corner there: approaching from the left gives slope -1 and from the right gives slope +1 - since these one-sided derivatives disagree, the function is not differentiable at that point.

Concept context

When a function has no breaks (continuity) and when it has a well-defined slope (differentiability), plus rules for differentiating implicit, inverse trig, exponential, log, and parametric functions.

Read the full Continuity and Differentiability notes →