Zaymiey

📐 Mathematics  ·  Continuity and Differentiability  ·  JEE

If x = at<sup>2</sup> and y = 2at (parametric form), then dy/dx is found using:

Answer: dy/dx = (dy/dt) divided by (dx/dt).

  • A dy/dx = dx/dt divided by dy/dt
  • B dy/dx = (dy/dt) divided by (dx/dt)
  • C dy/dx = dy/dt times dx/dt
  • D dy/dx = dt/dy

Correct answer: B. dy/dx = (dy/dt) divided by (dx/dt)

Explanation: For parametric curves, dy/dx = (dy/dt) / (dx/dt), provided dx/dt is not zero.

f(x) = |x|: Continuous but NOT Differentiable at 0x=0 (sharp "kink")LHD = -1RHD = +1LHD ≠ RHD at the kink → not differentiable, even though the curve has no gap (continuous)

f(x)=|x| is perfectly continuous at x=0 (no break, no jump), but the curve has a sharp corner there: approaching from the left gives slope -1 and from the right gives slope +1 - since these one-sided derivatives disagree, the function is not differentiable at that point.

Concept context

When a function has no breaks (continuity) and when it has a well-defined slope (differentiability), plus rules for differentiating implicit, inverse trig, exponential, log, and parametric functions.

Read the full Continuity and Differentiability notes →