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📐 Mathematics  ·  Continuity and Differentiability  ·  JEE

If f(x) = x²·sin(1/x) for x ≠ 0 and f(0) = 0, then f'(0) equals:

Answer: 0.

  • A 0
  • B 1
  • C does not exist
  • D

Correct answer: A. 0

Explanation: f'(0) = lim (x sin(1/x)) as x → 0, which is 0 by the squeeze theorem.

f(x) = |x|: Continuous but NOT Differentiable at 0x=0 (sharp "kink")LHD = -1RHD = +1LHD ≠ RHD at the kink → not differentiable, even though the curve has no gap (continuous)

f(x)=|x| is perfectly continuous at x=0 (no break, no jump), but the curve has a sharp corner there: approaching from the left gives slope -1 and from the right gives slope +1 - since these one-sided derivatives disagree, the function is not differentiable at that point.

Concept context

When a function has no breaks (continuity) and when it has a well-defined slope (differentiability), plus rules for differentiating implicit, inverse trig, exponential, log, and parametric functions.

Read the full Continuity and Differentiability notes →