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📐 Mathematics  ·  Continuity and Differentiability  ·  JEE

If f is differentiable with f(x + y) = f(x)f(y), f(0) = 1 and f'(0) = 2, then f'(x) equals:

Answer: 2f(x).

  • A f(x)
  • B 2f(x)
  • C 2x
  • D 2

Correct answer: B. 2f(x)

Explanation: Such an f is e<sup>2x</sup>, and f'(x) = 2e<sup>2x</sup> = 2f(x).

f(x) = |x|: Continuous but NOT Differentiable at 0x=0 (sharp "kink")LHD = -1RHD = +1LHD ≠ RHD at the kink → not differentiable, even though the curve has no gap (continuous)

f(x)=|x| is perfectly continuous at x=0 (no break, no jump), but the curve has a sharp corner there: approaching from the left gives slope -1 and from the right gives slope +1 - since these one-sided derivatives disagree, the function is not differentiable at that point.

Concept context

When a function has no breaks (continuity) and when it has a well-defined slope (differentiability), plus rules for differentiating implicit, inverse trig, exponential, log, and parametric functions.

Read the full Continuity and Differentiability notes →