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📐 Mathematics  ·  Continuity and Differentiability  ·  JEE

Find d<sup>2y</sup>/dx<sup>2</sup> if y = e<sup>x</sup> sin x.

Answer: 2e x cos x.

  • A 2e<sup>x</sup> cos x
  • B 2e<sup>x</sup>(cos x - sin x)
  • C 2e<sup>x</sup> sin x
  • D e<sup>x</sup>(cos x - sin x)

Correct answer: A. 2e<sup>x</sup> cos x

Explanation: Product rule: dy/dx = eˣ sin x + eˣ cos x = eˣ(sin x + cos x). Differentiate again: d²y/dx² = eˣ(sin x + cos x) + eˣ(cos x − sin x) = eˣ(2cos x) = 2eˣ cos x.

f(x) = |x|: Continuous but NOT Differentiable at 0x=0 (sharp "kink")LHD = -1RHD = +1LHD ≠ RHD at the kink → not differentiable, even though the curve has no gap (continuous)

f(x)=|x| is perfectly continuous at x=0 (no break, no jump), but the curve has a sharp corner there: approaching from the left gives slope -1 and from the right gives slope +1 - since these one-sided derivatives disagree, the function is not differentiable at that point.

Concept context

When a function has no breaks (continuity) and when it has a well-defined slope (differentiability), plus rules for differentiating implicit, inverse trig, exponential, log, and parametric functions.

Read the full Continuity and Differentiability notes →