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📐 Mathematics  ·  Continuity and Differentiability  ·  JEE

Differentiate y = x<sup>x</sup> using logarithmic differentiation.

Answer: dy/dx = x x (1 + ln x).

  • A dy/dx = x<sup>x</sup>
  • B dy/dx = x<sup>x</sup> (1 + ln x)
  • C dy/dx = x times x<sup>x-1</sup>
  • D dy/dx = x<sup>x</sup> ln x

Correct answer: B. dy/dx = x<sup>x</sup> (1 + ln x)

Explanation: Take ln: ln y = x ln x. Differentiate: (1/y)(dy/dx) = ln x + 1. So dy/dx = y(1 + ln x) = x<sup>x</sup>(1 + ln x).

f(x) = |x|: Continuous but NOT Differentiable at 0x=0 (sharp "kink")LHD = -1RHD = +1LHD ≠ RHD at the kink → not differentiable, even though the curve has no gap (continuous)

f(x)=|x| is perfectly continuous at x=0 (no break, no jump), but the curve has a sharp corner there: approaching from the left gives slope -1 and from the right gives slope +1 - since these one-sided derivatives disagree, the function is not differentiable at that point.

Concept context

When a function has no breaks (continuity) and when it has a well-defined slope (differentiability), plus rules for differentiating implicit, inverse trig, exponential, log, and parametric functions.

Read the full Continuity and Differentiability notes →