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📐 Mathematics  ·  Continuity and Differentiability  ·  JEE

By Rolle's theorem, the value c in (−2, 2) for f(x) = x² − 4 is:

Answer: 0.

  • A −1
  • B 0
  • C 1
  • D 2

Correct answer: B. 0

Explanation: f'(x) = 2x = 0 gives c = 0.

f(x) = |x|: Continuous but NOT Differentiable at 0x=0 (sharp "kink")LHD = -1RHD = +1LHD ≠ RHD at the kink → not differentiable, even though the curve has no gap (continuous)

f(x)=|x| is perfectly continuous at x=0 (no break, no jump), but the curve has a sharp corner there: approaching from the left gives slope -1 and from the right gives slope +1 - since these one-sided derivatives disagree, the function is not differentiable at that point.

Concept context

When a function has no breaks (continuity) and when it has a well-defined slope (differentiability), plus rules for differentiating implicit, inverse trig, exponential, log, and parametric functions.

Read the full Continuity and Differentiability notes →