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📐 Mathematics  ·  Continuity and Differentiability  ·  JEE

By Rolle's Theorem applied to f(x) = x<sup>2</sup> - 4x + 3 on [1,3], at which point is f'(c) = 0?

Answer: c = 2.

  • A c = 1
  • B c = 2
  • C c = 3
  • D c = 1.5

Correct answer: B. c = 2

Explanation: f(1) = 0 = f(3), satisfying the hypothesis. f'(x) = 2x - 4 = 0 gives x = 2, which lies in (1,3).

f(x) = |x|: Continuous but NOT Differentiable at 0x=0 (sharp "kink")LHD = -1RHD = +1LHD ≠ RHD at the kink → not differentiable, even though the curve has no gap (continuous)

f(x)=|x| is perfectly continuous at x=0 (no break, no jump), but the curve has a sharp corner there: approaching from the left gives slope -1 and from the right gives slope +1 - since these one-sided derivatives disagree, the function is not differentiable at that point.

Concept context

When a function has no breaks (continuity) and when it has a well-defined slope (differentiability), plus rules for differentiating implicit, inverse trig, exponential, log, and parametric functions.

Read the full Continuity and Differentiability notes →