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📐 Mathematics  ·  Complex Numbers and Quadratic Equations  ·  JEE

Using De Moivre theorem, find (1 + i)⁸.

Answer: 16.

  • A 8
  • B 16
  • C 16i
  • D -16

Correct answer: B. 16

Explanation: 1+i = sqrt(2)(cos(pi/4)+i sin(pi/4)). (1+i)<sup>8</sup> = (sqrt(2))<sup>8</sup> (cos(8*pi/4)+i sin(8*pi/4)) = 16(cos 2pi + i sin 2pi) = 16(1+0) = 16.

Argand Plane: z = a + ibReImz = a+iba (real part)b (imaginary part)θ = arg(z)|z| = length of the vector OZ = √(a²+b²); θ = angle OZ makes with the positive real axis

A complex number z = a+ib is plotted as a point (or vector from the origin) on the Argand plane, with the real part along the horizontal axis and the imaginary part along the vertical; its modulus |z| is the vector's length, and its argument θ is the angle from the positive real axis.

Concept context

Complex numbers in a+ib form, modulus, argument, polar form, cube roots of unity, and quadratic equations with complex roots

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