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📐 Mathematics  ·  Complex Numbers and Quadratic Equations  ·  JEE

The smallest positive integer n for which (1+i)<sup>2n</sup> = (1-i)<sup>2n</sup> is:

Answer: 2.

  • A 1
  • B 2
  • C 3
  • D 4

Correct answer: B. 2

Explanation: Compute squares: (1+i)²=1+2i-1=2i and (1-i)²=1-2i-1=-2i. So equation becomes (2i)<sup>n</sup>=(-2i)<sup>n</sup>, i.e., 2<sup>n</sup>·i<sup>n</sup> = 2<sup>n</sup>·(-i)<sup>n</sup>, giving i<sup>n</sup>=(-i)<sup>n</sup>, or (i/(-i))<sup>n</sup>=(-1)<sup>n</sup>=1. Smallest positive n: n=2. Answer: n = 2

Argand Plane: z = a + ibReImz = a+iba (real part)b (imaginary part)θ = arg(z)|z| = length of the vector OZ = √(a²+b²); θ = angle OZ makes with the positive real axis

A complex number z = a+ib is plotted as a point (or vector from the origin) on the Argand plane, with the real part along the horizontal axis and the imaginary part along the vertical; its modulus |z| is the vector's length, and its argument θ is the angle from the positive real axis.

Concept context

Complex numbers in a+ib form, modulus, argument, polar form, cube roots of unity, and quadratic equations with complex roots

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