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📐 Mathematics  ·  Complex Numbers and Quadratic Equations  ·  JEE

If arg(z) = π/4 and |z| = 2, find z².

Answer: 4i.

  • A 2i
  • B 4
  • C 2+2i
  • D 4i

Correct answer: D. 4i

Explanation: De Moivre's theorem: z=|z|(cosθ+i sinθ)=2(cos π/4+i sin π/4). Then z²=|z|²(cos 2θ+i sin 2θ)=4(cos π/2+i sin π/2)=4(0+i·1)=4i. So |z²|=4, arg(z²)=π/2. Answer: z² = 4i

Argand Plane: z = a + ibReImz = a+iba (real part)b (imaginary part)θ = arg(z)|z| = length of the vector OZ = √(a²+b²); θ = angle OZ makes with the positive real axis

A complex number z = a+ib is plotted as a point (or vector from the origin) on the Argand plane, with the real part along the horizontal axis and the imaginary part along the vertical; its modulus |z| is the vector's length, and its argument θ is the angle from the positive real axis.

Concept context

Complex numbers in a+ib form, modulus, argument, polar form, cube roots of unity, and quadratic equations with complex roots

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