Answer: 128.
- A 64
- B −64
- C 128
- D −128
Correct answer: C. 128
Explanation: The roots are 2e<sup>±iπ/3</sup>. So α⁶ + β⁶ = 2·2⁶·cos(2π) = 128.
A complex number z = a+ib is plotted as a point (or vector from the origin) on the Argand plane, with the real part along the horizontal axis and the imaginary part along the vertical; its modulus |z| is the vector's length, and its argument θ is the angle from the positive real axis.
Concept context
Complex numbers in a+ib form, modulus, argument, polar form, cube roots of unity, and quadratic equations with complex roots
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