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📐 Mathematics  ·  Complex Numbers and Quadratic Equations  ·  JEE

If alpha, beta are roots of x² - px + q = 0, find alpha<sup>4</sup> + beta<sup>4.</sup>

Answer: Both A and B.

  • A (p²-2q)² - 2q²
  • B p<sup>4</sup> - 4p²q + 2q²
  • C (p²-q)² - q²
  • D Both A and B

Correct answer: D. Both A and B

Explanation: alpha²+beta² = p²-2q. alpha<sup>4</sup>+beta<sup>4</sup> = (alpha²+beta²)² - 2(alpha×beta)² = (p²-2q)² - 2q². Expanding: p<sup>4</sup>-4p²q+4q²-2q² = p<sup>4</sup>-4p²q+2q². Both expressions are equal.

Argand Plane: z = a + ibReImz = a+iba (real part)b (imaginary part)θ = arg(z)|z| = length of the vector OZ = √(a²+b²); θ = angle OZ makes with the positive real axis

A complex number z = a+ib is plotted as a point (or vector from the origin) on the Argand plane, with the real part along the horizontal axis and the imaginary part along the vertical; its modulus |z| is the vector's length, and its argument θ is the angle from the positive real axis.

Concept context

Complex numbers in a+ib form, modulus, argument, polar form, cube roots of unity, and quadratic equations with complex roots

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