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📐 Mathematics  ·  Complex Numbers and Quadratic Equations  ·  JEE

De Moivre theorem: (cos θ + i sin θ)ⁿ =

Answer: cos nθ + i sin nθ.

  • A n cos θ + ni sin θ
  • B cos θⁿ + i sin θⁿ
  • C cos(θ/n) + i sin(θ/n)
  • D cos nθ + i sin nθ

Correct answer: D. cos nθ + i sin nθ

Explanation: De Moivre theorem: (cos theta + i sin theta)<sup>n</sup> = cos(n*theta) + i sin(n*theta).

Argand Plane: z = a + ibReImz = a+iba (real part)b (imaginary part)θ = arg(z)|z| = length of the vector OZ = √(a²+b²); θ = angle OZ makes with the positive real axis

A complex number z = a+ib is plotted as a point (or vector from the origin) on the Argand plane, with the real part along the horizontal axis and the imaginary part along the vertical; its modulus |z| is the vector's length, and its argument θ is the angle from the positive real axis.

Concept context

Complex numbers in a+ib form, modulus, argument, polar form, cube roots of unity, and quadratic equations with complex roots

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