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📐 Mathematics  ·  Circles & Mensuration  ·  JEE

The radius of the circle passing through (0, 0), (4, 0) and (0, 6) is:

Answer: √13.

  • A √11
  • B √13
  • C 5
  • D √26

Correct answer: B. √13

Explanation: The circle is x² + y² − 4x − 6y = 0 with centre (2, 3), radius √(4 + 9) = √13.

Cylinder, Cone, SphereV=πr²hCSA=2πrhV=⅓πr²hCSA=πrlV=4/3πr³SA=4πr²

Three standard 3D solids and their key formulas: a cylinder's volume scales with the full height, a cone's volume is exactly one-third of the cylinder with the same base and height, and a sphere's volume and surface area both follow distinct r-based formulas worth memorising separately.

Concept context

Perimeters, areas, and volumes of 2D and 3D shapes

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