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📐 Mathematics  ·  Circles & Mensuration  ·  JEE

Ptolemy theorem for a cyclic quadrilateral ABCD states:

Answer: AC × BD = AB × CD + AD × BC.

  • A AC × BD = AB × CD + AD × BC
  • B AC + BD = AB + CD, an additive but incorrect form
  • C AC/BD = AB/CD, a ratio form that does not hold generally
  • D AC × BD = AB × AD, missing the CD term from the product

Correct answer: A. AC × BD = AB × CD + AD × BC

Explanation: For a cyclic quadrilateral, Ptolemy proved: product of diagonals = sum of products of opposite side pairs. Diagonal AC, BD; sides AB,CD and AD,BC: AC×BD=AB×CD+AD×BC. Verified for a rectangle (special case). Ans: AC×BD=AB×CD+AD×BC.

Cylinder, Cone, SphereV=πr²hCSA=2πrhV=⅓πr²hCSA=πrlV=4/3πr³SA=4πr²

Three standard 3D solids and their key formulas: a cylinder's volume scales with the full height, a cone's volume is exactly one-third of the cylinder with the same base and height, and a sphere's volume and surface area both follow distinct r-based formulas worth memorising separately.

Concept context

Perimeters, areas, and volumes of 2D and 3D shapes

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