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📐 Mathematics  ·  Circles & Mensuration  ·  JEE

For a frustum with top radius r, bottom radius R, height h, slant height l = √(h²+(R-r)²). Lateral SA =

Answer: π(R+r)l.

  • A π(R+r)l
  • B πl(R-r)
  • C 2πl(R+r)
  • D π(R²-r²)

Correct answer: A. π(R+r)l

Explanation: Unrolling the frustum gives a trapezoidal band. Lateral SA = π(R+r)l, where l=√(h²+(R−r)²) is the slant height. This is derived by subtracting the lateral area of the smaller cone from the larger. Ans: π(R+r)l.

Cylinder, Cone, SphereV=πr²hCSA=2πrhV=⅓πr²hCSA=πrlV=4/3πr³SA=4πr²

Three standard 3D solids and their key formulas: a cylinder's volume scales with the full height, a cone's volume is exactly one-third of the cylinder with the same base and height, and a sphere's volume and surface area both follow distinct r-based formulas worth memorising separately.

Concept context

Perimeters, areas, and volumes of 2D and 3D shapes

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