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📐 Mathematics  ·  Application of Integrals  ·  JEE

The area enclosed by a semicircle of radius r above the x-axis (y = sqrt(r<sup>2</sup>-x<sup>2</sup>)) is:

Answer: (pi r 2 )/2.

  • A pi r<sup>2</sup>
  • B (pi r<sup>2</sup>)/2
  • C 2 pi r
  • D pi r

Correct answer: B. (pi r<sup>2</sup>)/2

Explanation: A semicircle is half of a full circle, so its area is (pi r<sup>2</sup>)/2.

Area Under a Curve = Definite Integralxyx=ax=bArea = ∫ₐᵇ f(x)dx

The definite integral ∫ₐᵇf(x)dx computes the exact area of the shaded region bounded by the curve, the x-axis, and the vertical lines x=a and x=b - the same idea behind the Riemann sum, but evaluated exactly rather than approximated by rectangles.

Concept context

Using definite integrals to compute the area under a curve, the area between two curves, and the areas enclosed by standard curves like circles, parabolas, and ellipses.

Read the full Application of Integrals notes →