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📐 Mathematics  ·  Application of Integrals  ·  JEE

The area enclosed by the ellipse x<sup>2</sup>/a<sup>2</sup> + y<sup>2</sup>/b<sup>2</sup> = 1 is:

Answer: pi a b.

  • A pi a b
  • B pi(a+b)
  • C pi a<sup>2</sup> b<sup>2</sup>
  • D 2 pi a b

Correct answer: A. pi a b

Explanation: By integration over the ellipse (4 times the first-quadrant area), the total enclosed area is pi a b.

Area Under a Curve = Definite Integralxyx=ax=bArea = ∫ₐᵇ f(x)dx

The definite integral ∫ₐᵇf(x)dx computes the exact area of the shaded region bounded by the curve, the x-axis, and the vertical lines x=a and x=b - the same idea behind the Riemann sum, but evaluated exactly rather than approximated by rectangles.

Concept context

Using definite integrals to compute the area under a curve, the area between two curves, and the areas enclosed by standard curves like circles, parabolas, and ellipses.

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