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📐 Mathematics  ·  Application of Integrals  ·  JEE

The area enclosed between y² = 4x and x² = 4y is:

Answer: 16/3.

  • A 8/3
  • B 16/3
  • C 32/3
  • D 16

Correct answer: B. 16/3

Explanation: The two parabolas meet at (0,0) and (4,4); the enclosed area is 16/3.

Area Under a Curve = Definite Integralxyx=ax=bArea = ∫ₐᵇ f(x)dx

The definite integral ∫ₐᵇf(x)dx computes the exact area of the shaded region bounded by the curve, the x-axis, and the vertical lines x=a and x=b - the same idea behind the Riemann sum, but evaluated exactly rather than approximated by rectangles.

Concept context

Using definite integrals to compute the area under a curve, the area between two curves, and the areas enclosed by standard curves like circles, parabolas, and ellipses.

Read the full Application of Integrals notes →