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📐 Mathematics  ·  Application of Integrals  ·  JEE

Find the area of the smaller region bounded by the ellipse x<sup>2</sup>/9 + y<sup>2</sup>/4 = 1 and the line x/3 + y/2 = 1.

Answer: 3(pi - 2)/2.

  • A 3(pi - 2)/2
  • B 3pi - 6
  • C pi - 2
  • D 6(pi - 2)

Correct answer: A. 3(pi - 2)/2

Explanation: Using the standard NCERT technique (integrating the ellipse boundary minus the line, from x=0 to x=3), the smaller region's area simplifies to 3(pi-2)/2.

Area Under a Curve = Definite Integralxyx=ax=bArea = ∫ₐᵇ f(x)dx

The definite integral ∫ₐᵇf(x)dx computes the exact area of the shaded region bounded by the curve, the x-axis, and the vertical lines x=a and x=b - the same idea behind the Riemann sum, but evaluated exactly rather than approximated by rectangles.

Concept context

Using definite integrals to compute the area under a curve, the area between two curves, and the areas enclosed by standard curves like circles, parabolas, and ellipses.

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