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📐 Mathematics  ·  Application of Integrals  ·  JEE

Find the area of the region in the first quadrant bounded by y = 4 - x<sup>2</sup>, the x-axis, and the y-axis.

Answer: 16/3.

  • A 8
  • B 16/3
  • C 32/3
  • D 4

Correct answer: B. 16/3

Explanation: The curve meets the x-axis at x=2. Area = integral from 0 to 2 of (4-x<sup>2</sup>) dx = [4x - x<sup>3</sup>/3] from 0 to 2 = 8 - 8/3 = 16/3.

Area Under a Curve = Definite Integralxyx=ax=bArea = ∫ₐᵇ f(x)dx

The definite integral ∫ₐᵇf(x)dx computes the exact area of the shaded region bounded by the curve, the x-axis, and the vertical lines x=a and x=b - the same idea behind the Riemann sum, but evaluated exactly rather than approximated by rectangles.

Concept context

Using definite integrals to compute the area under a curve, the area between two curves, and the areas enclosed by standard curves like circles, parabolas, and ellipses.

Read the full Application of Integrals notes →