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📐 Mathematics  ·  Application of Integrals  ·  JEE

Find the area common to the circle x<sup>2</sup>+y<sup>2</sup> = 4 and the line x = 1 (area of the circular region to the right of x=1).

Answer: (4pi/3) - sqrt(3).

  • A (4pi/3) - sqrt(3)
  • B (2pi/3) - sqrt(3)/2
  • C (8pi/3) - 2sqrt(3)
  • D pi - sqrt(3)

Correct answer: A. (4pi/3) - sqrt(3)

Explanation: Area to the right of x=1 inside x<sup>2</sup>+y<sup>2</sup>=4 is 2 times integral from 1 to 2 of sqrt(4-x<sup>2</sup>) dx, which evaluates using the standard formula integral sqrt(a<sup>2</sup>-x<sup>2</sup>)dx = (x/2)sqrt(a<sup>2</sup>-x<sup>2</sup>)+(a<sup>2</sup>/2)sin-1(x/a), giving total area = (4pi/3) - sqrt(3).

Area Under a Curve = Definite Integralxyx=ax=bArea = ∫ₐᵇ f(x)dx

The definite integral ∫ₐᵇf(x)dx computes the exact area of the shaded region bounded by the curve, the x-axis, and the vertical lines x=a and x=b - the same idea behind the Riemann sum, but evaluated exactly rather than approximated by rectangles.

Concept context

Using definite integrals to compute the area under a curve, the area between two curves, and the areas enclosed by standard curves like circles, parabolas, and ellipses.

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