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📐 Mathematics  ·  Application of Integrals  ·  JEE

Area under y = sqrt(x) from x = 0 to x = 4 is:

Answer: 16/3.

  • A 8/3
  • B 16/3
  • C 4
  • D 2

Correct answer: B. 16/3

Explanation: Integral of x<sup>1/2</sup> dx from 0 to 4 = [(2/3)x<sup>3/2</sup>] from 0 to 4 = (2/3)(8) - 0 = 16/3.

Area Under a Curve = Definite Integralxyx=ax=bArea = ∫ₐᵇ f(x)dx

The definite integral ∫ₐᵇf(x)dx computes the exact area of the shaded region bounded by the curve, the x-axis, and the vertical lines x=a and x=b - the same idea behind the Riemann sum, but evaluated exactly rather than approximated by rectangles.

Concept context

Using definite integrals to compute the area under a curve, the area between two curves, and the areas enclosed by standard curves like circles, parabolas, and ellipses.

Read the full Application of Integrals notes →