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🧪 Chemistry  ·  Redox Reactions  ·  NEET & JEE

What is the oxidation state of sulphur in peroxomonosulphuric acid (Caro acid, H<sub>2</sub>SO<sub>5</sub>)?

Answer: +6 (one S-OH and one S-O-O-H group making it a peroxoacid).

  • A +6 (one S-OH and one S-O-O-H group making it a peroxoacid)
  • B +4, the oxidation state characteristic of sulfur in SO<sub>2</sub> instead
  • C +8, an oxidation state not actually accessible to sulfur in any compound
  • D +2, an unusually low oxidation state not seen in this peroxoacid

Correct answer: A. +6 (one S-OH and one S-O-O-H group making it a peroxoacid)

Explanation: H₂SO₅ is peroxomonosulphuric acid (also called Caro acid). The peroxy O-O linkage contributes -1 per O (not -2). 2(+1) + S + 4(-2) + 1(-1) = 0, giving S = +6. The S is +6 but one O is the peroxide type (-1).

Electron Transfer: Zn + Cu²⁺ → Zn²⁺ + CuZnloses 2e⁻OXIDISED (Zn → Zn²⁺)2e⁻Cu²⁺gains 2e⁻REDUCED (Cu²⁺ → Cu)Zn = reducing agentCu²⁺ = oxidising agent

Electron transfer in a redox reaction: zinc loses electrons (oxidised, acts as reducing agent) and copper(II) ions gain those same electrons (reduced, acts as oxidising agent).

Concept context

Master electron transfer in chemistry: assign oxidation states, balance half-reactions, identify oxidising and reducing agents, and connect redox to everyday reactions.

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