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🧪 Chemistry  ·  Redox Reactions  ·  NEET & JEE

The oxidation number of oxygen in oxygen difluoride (OF<sub>2</sub>) is:

Answer: +2.

  • A −2
  • B −1
  • C +2
  • D 0

Correct answer: C. +2

Explanation: Fluorine is more electronegative than oxygen, so each F is −1 and oxygen is forced to +2 in OF<sub>2</sub>.

Electron Transfer: Zn + Cu²⁺ → Zn²⁺ + CuZnloses 2e⁻OXIDISED (Zn → Zn²⁺)2e⁻Cu²⁺gains 2e⁻REDUCED (Cu²⁺ → Cu)Zn = reducing agentCu²⁺ = oxidising agent

Electron transfer in a redox reaction: zinc loses electrons (oxidised, acts as reducing agent) and copper(II) ions gain those same electrons (reduced, acts as oxidising agent).

Concept context

Master electron transfer in chemistry: assign oxidation states, balance half-reactions, identify oxidising and reducing agents, and connect redox to everyday reactions.

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