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🧪 Chemistry  ·  Redox Reactions  ·  NEET & JEE

What is the oxidation state of iron in Fe<sub>3</sub>O<sub>4</sub>?

Answer: Mixed: 1/3 Fe 2+ and 2/3 Fe 3+ (average +8/3).

  • A All iron present as Fe<sup>2+</sup> throughout the entire compound
  • B All iron present as Fe<sup>3+</sup> throughout the entire compound
  • C Mixed: 1/3 Fe<sup>2+</sup> and 2/3 Fe<sup>3+</sup> (average +8/3)
  • D All iron present as the unusually high Fe<sup>4+</sup> oxidation state

Correct answer: C. Mixed: 1/3 Fe<sup>2+</sup> and 2/3 Fe<sup>3+</sup> (average +8/3)

Explanation: Fe₃O₄ is a mixed oxide: FeO·Fe₂O₃. It contains one Fe²⁺ and two Fe³⁺ per formula unit. Average oxidation state = (2 + 3 + 3)/3 = 8/3 ≈ +2.67.

Electron Transfer: Zn + Cu²⁺ → Zn²⁺ + CuZnloses 2e⁻OXIDISED (Zn → Zn²⁺)2e⁻Cu²⁺gains 2e⁻REDUCED (Cu²⁺ → Cu)Zn = reducing agentCu²⁺ = oxidising agent

Electron transfer in a redox reaction: zinc loses electrons (oxidised, acts as reducing agent) and copper(II) ions gain those same electrons (reduced, acts as oxidising agent).

Concept context

Master electron transfer in chemistry: assign oxidation states, balance half-reactions, identify oxidising and reducing agents, and connect redox to everyday reactions.

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