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🧪 Chemistry  ·  Redox Reactions  ·  NEET & JEE

What is the n-factor (equivalents per mole) of KMnO<sub>4</sub> in neutral/faintly alkaline medium?

Answer: 3.

  • A 5
  • B 3
  • C 1
  • D 7

Correct answer: B. 3

Explanation: In acidic medium, Mn goes from +7 to +2 (n-factor = 5). In neutral or faintly alkaline medium, MnO₄⁻ is reduced to MnO₂ (Mn +4); n-factor = 7 - 4 = 3.

Electron Transfer: Zn + Cu²⁺ → Zn²⁺ + CuZnloses 2e⁻OXIDISED (Zn → Zn²⁺)2e⁻Cu²⁺gains 2e⁻REDUCED (Cu²⁺ → Cu)Zn = reducing agentCu²⁺ = oxidising agent

Electron transfer in a redox reaction: zinc loses electrons (oxidised, acts as reducing agent) and copper(II) ions gain those same electrons (reduced, acts as oxidising agent).

Concept context

Master electron transfer in chemistry: assign oxidation states, balance half-reactions, identify oxidising and reducing agents, and connect redox to everyday reactions.

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