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What is the change in oxidation state of sulphur when H<sub>2</sub>S is converted to SO<sub>2</sub>?

Answer: -2 to +4 (change of +6).

  • A -2 to +2 (change of +4)
  • B 0 to +4 (change of +4)
  • C -2 to +4 (change of +6)
  • D +2 to +4 (change of +2)

Correct answer: C. -2 to +4 (change of +6)

Explanation: In H₂S, S is -2. In SO₂, S is +4. The change in oxidation state is +4 - (-2) = +6; sulphur is oxidised (loses 6 electrons).

Electron Transfer: Zn + Cu²⁺ → Zn²⁺ + CuZnloses 2e⁻OXIDISED (Zn → Zn²⁺)2e⁻Cu²⁺gains 2e⁻REDUCED (Cu²⁺ → Cu)Zn = reducing agentCu²⁺ = oxidising agent

Electron transfer in a redox reaction: zinc loses electrons (oxidised, acts as reducing agent) and copper(II) ions gain those same electrons (reduced, acts as oxidising agent).

Concept context

Master electron transfer in chemistry: assign oxidation states, balance half-reactions, identify oxidising and reducing agents, and connect redox to everyday reactions.

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