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🧪 Chemistry  ·  Redox Reactions  ·  NEET & JEE

The oxidation state of sulphur in H<sub>2</sub>SO<sub>4</sub> is:

Answer: +6.

  • A +4
  • B +6
  • C -2
  • D +2

Correct answer: B. +6

Explanation: In H₂SO₄: 2(+1) + S + 4(-2) = 0. S = 8 - 2 = +6.

Electron Transfer: Zn + Cu²⁺ → Zn²⁺ + CuZnloses 2e⁻OXIDISED (Zn → Zn²⁺)2e⁻Cu²⁺gains 2e⁻REDUCED (Cu²⁺ → Cu)Zn = reducing agentCu²⁺ = oxidising agent

Electron transfer in a redox reaction: zinc loses electrons (oxidised, acts as reducing agent) and copper(II) ions gain those same electrons (reduced, acts as oxidising agent).

Concept context

Master electron transfer in chemistry: assign oxidation states, balance half-reactions, identify oxidising and reducing agents, and connect redox to everyday reactions.

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