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🧪 Chemistry  ·  Redox Reactions  ·  NEET & JEE

The n-factor of oxalic acid acting as a reductant (C<sub>2</sub>O<sub>4</sub><sup>2−</sup> → 2CO<sub>2</sub>) is:

Answer: 2.

  • A 1
  • B 3
  • C 4
  • D 2

Correct answer: D. 2

Explanation: Each carbon changes from +3 to +4; with two carbons the total change is 2 electrons, so the n-factor is 2.

Electron Transfer: Zn + Cu²⁺ → Zn²⁺ + CuZnloses 2e⁻OXIDISED (Zn → Zn²⁺)2e⁻Cu²⁺gains 2e⁻REDUCED (Cu²⁺ → Cu)Zn = reducing agentCu²⁺ = oxidising agent

Electron transfer in a redox reaction: zinc loses electrons (oxidised, acts as reducing agent) and copper(II) ions gain those same electrons (reduced, acts as oxidising agent).

Concept context

Master electron transfer in chemistry: assign oxidation states, balance half-reactions, identify oxidising and reducing agents, and connect redox to everyday reactions.

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