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🧪 Chemistry  ·  Redox Reactions  ·  NEET & JEE

The equivalent weight of K<sub>2</sub>Cr<sub>2</sub>O<sub>7</sub> in acidic medium (where Cr goes from +6 to +3) is:

Answer: Molar mass / 6.

  • A Molar mass / 3
  • B Molar mass / 6
  • C Molar mass / 1
  • D Molar mass / 2

Correct answer: B. Molar mass / 6

Explanation: In K₂Cr₂O₇: each Cr goes from +6 to +3 (change of 3 per Cr); two Cr atoms change, so total electron transfer per mole = 6 (n-factor = 6). Equivalent weight = Molar mass / n-factor = M/6.

Electron Transfer: Zn + Cu²⁺ → Zn²⁺ + CuZnloses 2e⁻OXIDISED (Zn → Zn²⁺)2e⁻Cu²⁺gains 2e⁻REDUCED (Cu²⁺ → Cu)Zn = reducing agentCu²⁺ = oxidising agent

Electron transfer in a redox reaction: zinc loses electrons (oxidised, acts as reducing agent) and copper(II) ions gain those same electrons (reduced, acts as oxidising agent).

Concept context

Master electron transfer in chemistry: assign oxidation states, balance half-reactions, identify oxidising and reducing agents, and connect redox to everyday reactions.

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