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🧪 Chemistry  ·  Redox Reactions  ·  NEET & JEE

The disproportionation of H<sub>3</sub>PO<sub>3</sub> (phosphorous acid) on heating gives H<sub>3</sub>PO<sub>4</sub> and:

Answer: PH 3.

  • A PH<sub>3</sub>
  • B P<sub>2</sub>O<sub>5</sub>
  • C P<sub>4</sub>
  • D H<sub>3</sub>PO<sub>2</sub>

Correct answer: A. PH<sub>3</sub>

Explanation: H₃PO₃ has P in +3 oxidation state. On heating: 4H₃PO₃ → 3H₃PO₄ + PH₃. P goes from +3 to +5 (in H₃PO₄, oxidised) and +3 to -3 (in PH₃, reduced). This is disproportionation.

Electron Transfer: Zn + Cu²⁺ → Zn²⁺ + CuZnloses 2e⁻OXIDISED (Zn → Zn²⁺)2e⁻Cu²⁺gains 2e⁻REDUCED (Cu²⁺ → Cu)Zn = reducing agentCu²⁺ = oxidising agent

Electron transfer in a redox reaction: zinc loses electrons (oxidised, acts as reducing agent) and copper(II) ions gain those same electrons (reduced, acts as oxidising agent).

Concept context

Master electron transfer in chemistry: assign oxidation states, balance half-reactions, identify oxidising and reducing agents, and connect redox to everyday reactions.

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