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🧪 Chemistry  ·  Chemical Kinetics  ·  NEET & JEE

For a first-order reaction, a graph of ln[A] versus time gives a straight line. If the line has a slope of -0.0231 min<sup>-1</sup>, what is the half-life of the reaction?

Answer: 30 min.

  • A 60 min
  • B 15 min
  • C 30 min
  • D 23.1 min

Correct answer: C. 30 min

Explanation: Slope = -k, so k = 0.0231 min<sup>-1</sup>; t(1/2) = 0.693/k = 0.693/0.0231 = 30 min.

First-Order Decay: Constant Half-Lifetime[A][A]₀[A]₀/22 × t½[A]₀/4Each successive half-life takes the SAME amount of time, regardless of starting concentration

First-order decay curve: concentration halves every t½, and that half-life is constant - a defining test for first-order kinetics.

Concept context

Study the speed of reactions and what affects it: concentration, temperature, and catalysts. Covers rate law, order of reaction, the Arrhenius equation, and reaction mechanisms step by step.

Read the full Chemical Kinetics notes →