Answer: Exists as a cyclic hemiacetal lacking free CHO.
- A Contains five hydroxyl groups in a ring
- B Has a branched carbon skeleton in solution
- C Exists as a cyclic hemiacetal lacking free CHO
- D Is a non-reducing disaccharide in the solid state
Correct answer: C. Exists as a cyclic hemiacetal lacking free CHO
Explanation: The pentaacetate has no free aldehyde, so no oxime forms. This shows glucose exists largely in a cyclic hemiacetal form with no free CHO group.
Two amino acids join via a condensation reaction: the carboxyl -OH of one and an amine -H of the other are eliminated as water, leaving a peptide bond (-CO-NH-) linking them into a dipeptide; repeating this builds a full protein chain.
Concept context
The chemistry of life: carbohydrates, proteins, lipids, nucleic acids, enzymes, and vitamins. Understand their structures, classification, and biological functions. Highly relevant for NEET and Class 12 board exams.