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🧪 Chemistry  ·  Amines  ·  NEET & JEE

Reduction of propanenitrile (CH<sub>3</sub>CH<sub>2</sub>CN) with LiAlH<sub>4</sub> gives:

Answer: propan-1-amine.

  • A ethanamine
  • B propan-1-amine
  • C propan-2-amine
  • D N-methylethanamine

Correct answer: B. propan-1-amine

Explanation: A nitrile gains two hydrogens to become -CH<sub>2</sub>NH<sub>2</sub>, so propanenitrile gives the primary amine propan-1-amine.

Why Aniline Is a Weaker Base Than MethylamineNCH₃lone pair fully availableMethylamineN donates electrons freely → STRONG baseNlone pair delocalised into ringAniline

In aniline, the nitrogen's lone pair is pulled into the benzene ring through resonance, leaving less electron density available to accept a proton - which is why aniline is a much weaker base than methylamine, where the lone pair is fully available.

Concept context

Nitrogen-containing organic compounds. Covers classification (primary, secondary, tertiary), basicity comparison, preparation methods, and reactions including diazotization and coupling, key for understanding dyes and pharmaceuticals.

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