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🧪 Chemistry  ·  Amines  ·  NEET & JEE

Reaction of ethyl bromide with excess ammonia chiefly gives:

Answer: a mixture of amines of all classes.

  • A a pure sample of ethanamine
  • B only diethylamine is formed
  • C a mixture of amines of all classes
  • D only triethylamine is formed

Correct answer: C. a mixture of amines of all classes

Explanation: Ammonolysis is hard to stop at one stage; successive alkylation gives a mixture of primary, secondary and tertiary amines with the quaternary salt.

Why Aniline Is a Weaker Base Than MethylamineNCH₃lone pair fully availableMethylamineN donates electrons freely → STRONG baseNlone pair delocalised into ringAniline

In aniline, the nitrogen's lone pair is pulled into the benzene ring through resonance, leaving less electron density available to accept a proton - which is why aniline is a much weaker base than methylamine, where the lone pair is fully available.

Concept context

Nitrogen-containing organic compounds. Covers classification (primary, secondary, tertiary), basicity comparison, preparation methods, and reactions including diazotization and coupling, key for understanding dyes and pharmaceuticals.

Read the full Amines notes →