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🔬 Biology  ·  Evolution  ·  NEET

In the Hardy-Weinberg equation p<sup>2</sup> + 2pq + q<sup>2</sup> = 1, the term 2pq represents the frequency of:

Answer: heterozygous individuals.

  • A homozygous dominants
  • B heterozygous individuals
  • C homozygous recessives
  • D newly mutated alleles

Correct answer: B. heterozygous individuals

Explanation: In the Hardy-Weinberg expansion, p<sup>2</sup> is the homozygous dominant frequency, q<sup>2</sup> the homozygous recessive, and 2pq the heterozygotes.

Simple Phylogenetic TreeCommon ancestorLineage ALineage BLineage C1Lineage C2Branch points represent speciation events from a shared ancestor

A simple phylogenetic tree: a common ancestor branches into several descendant lineages over time, with each branch point marking a speciation event.

Concept context

Origin of life, Darwin's theory, natural selection, speciation, and evidence for evolution.

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