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The turnover number (kcat) of an enzyme represents

Answer: The number of substrate molecules converted per enzyme molecule per second.

  • A The fixed number of substrate molecules an enzyme requires to become active
  • B The number of substrate molecules converted per enzyme molecule per second
  • C The rate at which new enzyme molecules are transcribed and translated
  • D The rate at which a competitive inhibitor binds the enzyme's active site

Correct answer: B. The number of substrate molecules converted per enzyme molecule per second

Explanation: kcat (catalytic constant or turnover number) is the maximum number of substrate molecules converted to product per enzyme molecule per second. Catalase has a very high kcat (~4 million/s).

Enzyme Kinetics: Rate vs Substrate Concentration[Substrate]Reaction rateVmaxKm½VmaxCurve flattens at high [S]: ALL enzyme active sites are occupied (saturation)

As substrate concentration rises, reaction rate increases steeply at first, then plateaus at Vmax once every enzyme molecule is working at full capacity; Km is the substrate concentration giving half-maximal rate, and a LOWER Km means the enzyme reaches that rate with less substrate (higher affinity).

Concept context

Carbohydrates, proteins, lipids, nucleic acids, and enzyme kinetics. Essential foundation for understanding metabolism.

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