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⚛️ Physics  ·  Work, Energy and Power  ·  NEET & JEE

The speed of a 2 kg body increases from 3 m/s to 5 m/s. The work done on it is:

Answer: 16 J.

  • A 32 J
  • B 8 J
  • C 16 J
  • D 4 J

Correct answer: C. 16 J

Explanation: By the work-energy theorem, W = ½m(v<sup>2</sup> - u<sup>2</sup>) = ½ × 2 × (25 - 9) = 16 J.

Energy Conservation: KE ⇄ PE on a SwingA: PE maxKE = 0B: KE maxPE minC: PE maxKE = 0

As a pendulum swings, total mechanical energy (KE+PE) stays constant: at the highest points A and C, all energy is potential (zero speed); at the lowest point B, all of that energy has converted into kinetic energy (maximum speed).

Concept context

Work-energy theorem, potential energy, conservation of energy, collisions.

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